What is the value of cos(240-0) ?

The value of cos(240-0) is -1/2

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cos(240-0)

cos (24 0^{\circ} - 0^{\circ})

- \frac{1}{2}

Solution steps

cos (24 0^{\circ} - 0)

Simplify

= cos (24 0^{\circ})

Rewrite using trig identities:

cos (18 0^{\circ}) cos (6 0^{\circ}) - sin (18 0^{\circ}) sin (6 0^{\circ})

= cos (18 0^{\circ}) cos (6 0^{\circ}) - sin (18 0^{\circ}) sin (6 0^{\circ})

Use the following trivial identity:

cos (18 0^{\circ}) = (- 1)

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

Use the following trivial identity:

sin (18 0^{\circ}) = 0

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

= (- 1) \frac{1}{2} - 0 \cdot \frac{3}{2}

Simplify

= - \frac{1}{2}

cot (66. 5^{\circ})

cos (10 1^{\circ})

sec (8 0^{\circ})

arctan (\frac{6}{12})

arctan (- \frac{1}{7})