What is the value of cos(arcsin(3/5)-arccos(1/2)) ?

The value of cos(arcsin(3/5)-arccos(1/2)) is 2/5+(3sqrt(3))/(10)

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cos(arcsin(3/5)-arccos(1/2))

cos (arcsin (\frac{3}{5}) - arccos (\frac{1}{2}))

\frac{2}{5} + \frac{3 3}{10}

Solution steps

cos (arcsin (\frac{3}{5}) - arccos (\frac{1}{2}))

Rewrite using trig identities:

cos (arcsin (\frac{3}{5})) cos (arccos (\frac{1}{2})) + sin (arcsin (\frac{3}{5})) sin (arccos (\frac{1}{2}))

= cos (arcsin (\frac{3}{5})) cos (arccos (\frac{1}{2})) + sin (arcsin (\frac{3}{5})) sin (arccos (\frac{1}{2}))

Rewrite using trig identities:

cos (arcsin (\frac{3}{5})) = \frac{4}{5}

Rewrite using trig identities:

cos (arccos (\frac{1}{2})) = \frac{1}{2}

Rewrite using trig identities:

sin (arcsin (\frac{3}{5})) = \frac{3}{5}

Rewrite using trig identities:

sin (arccos (\frac{1}{2})) = \frac{3}{2}

= \frac{4}{5} \cdot \frac{1}{2} + \frac{3}{5} \cdot \frac{3}{2}

Simplify

\frac{4}{5} \cdot \frac{1}{2} + \frac{3}{5} \cdot \frac{3}{2} : \frac{2}{5} + \frac{3 3}{10}

= \frac{2}{5} + \frac{3 3}{10}

sec (\frac{11 π}{2})

arctan (\frac{9}{10})

arctan (\frac{2.9}{2.8})

sin (\frac{4 π}{11})

tan (1.58)

What is the value of cos(arcsin(3/5)-arccos(1/2)) ?
The value of cos(arcsin(3/5)-arccos(1/2)) is 2/5+(3sqrt(3))/(10)