What is the general solution for 2cos(θ)-1=0 ?

The general solution for 2cos(θ)-1=0 is θ= pi/3+2pin,θ=(5pi)/3+2pin

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2cos(θ)-1=0

2 cos (θ) - 1 = 0

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

2 cos (θ) - 1 = 0

Move

1

to the right side

2 cos (θ) = 1

Divide both sides by

2

cos (θ) = \frac{1}{2}

General solutions for

cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

sin (x) = 0.4

cos (\frac{3 π}{8})

tan (θ) + 1 = 0

arctan (\frac{π}{2})

sin (- \frac{3 π}{2})

What is the general solution for 2cos(θ)-1=0 ?
The general solution for 2cos(θ)-1=0 is θ= pi/3+2pin,θ=(5pi)/3+2pin