What is the value of cos((5pi}{18})cos((2pi)/9)-sin((5pi)/(18))sin(\frac{2pi)/9) ?

The value of cos((5pi}{18})cos((2pi)/9)-sin((5pi)/(18))sin(\frac{2pi)/9) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos((5pi}{18})cos((2pi)/9)-sin((5pi)/(18))sin(\frac{2pi)/9)

cos (\frac{5 π}{18}) cos (\frac{2 π}{9}) - sin (\frac{5 π}{18}) sin (\frac{2 π}{9})

0

Solution steps

cos (\frac{5 π}{18}) cos (\frac{2 π}{9}) - sin (\frac{5 π}{18}) sin (\frac{2 π}{9})

Rewrite using trig identities:

cos (\frac{π}{2})

= cos (\frac{π}{2})

Use the following trivial identity:

cos (\frac{π}{2}) = 0

= 0

arcsin (sin (- \frac{7 π}{6}))

cos (9 8^{\circ})

sin (17 5^{\circ})

tan (0) + sec (0)

arcsin (\frac{12}{54})

What is the value of cos((5pi}{18})cos((2pi)/9)-sin((5pi)/(18))sin(\frac{2pi)/9) ?
The value of cos((5pi}{18})cos((2pi)/9)-sin((5pi)/(18))sin(\frac{2pi)/9) is 0