What is the value of e^{cos(pi)}cos(pi)-e^{cos(pi)}sin^2(pi) ?

The value of e^{cos(pi)}cos(pi)-e^{cos(pi)}sin^2(pi) is -1/e

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^{cos(pi)}cos(pi)-e^{cos(pi)}sin^2(pi)

e^{c o s (π)} cos (π) - e^{c o s (π)} sin^{2} (π)

- \frac{1}{e}

Solution steps

e^{c o s (π)} cos (π) - e^{c o s (π)} sin^{2} (π)

Use the following trivial identity:

cos (π) = (- 1)

Use the following trivial identity:

sin (π) = 0

= e^{- 1} (- 1) - e^{- 1} \cdot 0^{2}

Simplify

e^{- 1} (- 1) - e^{- 1} \cdot 0^{2} : - \frac{1}{e}

= - \frac{1}{e}

cos (6 0^{\circ} + 22 5^{\circ})

2 sin (1 3^{\circ}) cos (1 3^{\circ})

- cos (\frac{π}{4}) - sin (\frac{π}{4})

15 \cdot cos (3 7^{\circ})

cos^{2} (16 0^{\circ})

What is the value of e^{cos(pi)}cos(pi)-e^{cos(pi)}sin^2(pi) ?
The value of e^{cos(pi)}cos(pi)-e^{cos(pi)}sin^2(pi) is -1/e