What is the value of 2cos(pi/2)+sin(2(pi/2)) ?

The value of 2cos(pi/2)+sin(2(pi/2)) is 0

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2cos(pi/2)+sin(2(pi/2))

2 cos (\frac{π}{2}) + sin (2 (\frac{π}{2}))

0

Solution steps

2 cos (\frac{π}{2}) + sin (2 (\frac{π}{2}))

= 2 cos (\frac{π}{2}) + sin (2 \cdot \frac{π}{2})

Use the following trivial identity:

cos (\frac{π}{2}) = 0

Rewrite using trig identities:

sin (2 \cdot \frac{π}{2}) = 0

= 2 \cdot 0 + 0

Simplify

= 0

300 \cdot cos (5 5^{\circ}) \cdot 42

20 cos (5 5^{\circ})

sec (arcsin (\frac{2 5}{5}))

sin (3 5^{\circ}) cos (1 0^{\circ}) + cos (3 5^{\circ}) sin (1 0^{\circ})

- sin^{2} (0)

What is the value of 2cos(pi/2)+sin(2(pi/2)) ?
The value of 2cos(pi/2)+sin(2(pi/2)) is 0