What is the value of (cos(30))^2-(sin(30))^2 ?

The value of (cos(30))^2-(sin(30))^2 is 1/2

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(cos(30))^2-(sin(30))^2

(cos (3 0^{\circ}))^{2} - (sin (3 0^{\circ}))^{2}

\frac{1}{2}

Solution steps

(cos (3 0^{\circ}))^{2} - (sin (3 0^{\circ}))^{2}

= cos^{2} (3 0^{\circ}) - sin^{2} (3 0^{\circ})

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

= (\frac{3}{2})^{2} - (\frac{1}{2})^{2}

Simplify

(\frac{3}{2})^{2} - (\frac{1}{2})^{2} : \frac{1}{2}

= \frac{1}{2}

cos (2 π) - sin (2 π)

arcsin (\frac{39}{74})

sec (6 9^{\circ})

\frac{48}{cos ( 3 7 ^{\circ} )}

cot (\frac{- 7 π}{4})

What is the value of (cos(30))^2-(sin(30))^2 ?
The value of (cos(30))^2-(sin(30))^2 is 1/2