What is the value of sin^2(pi/6)+cos^2(pi/6) ?

The value of sin^2(pi/6)+cos^2(pi/6) is 1

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sin^2(pi/6)+cos^2(pi/6)

sin^{2} (\frac{π}{6}) + cos^{2} (\frac{π}{6})

1

Solution steps

sin^{2} (\frac{π}{6}) + cos^{2} (\frac{π}{6})

Use the following trivial identity:

sin (\frac{π}{6}) = \frac{1}{2}

Use the following trivial identity:

cos (\frac{π}{6}) = \frac{3}{2}

= (\frac{1}{2})^{2} + (\frac{3}{2})^{2}

Simplify

(\frac{1}{2})^{2} + (\frac{3}{2})^{2} : 1

= 1

3 \cdot tan (3 0^{\circ})

\frac{1}{sec ^{2} ( 0 )}

600 \cdot cos (4 5^{\circ})

cos (4 5^{\circ}) cos (1 5^{\circ}) - sin (4 5^{\circ}) sin (1 5^{\circ})

tan^{2} (4 5^{\circ} - \frac{35}{2})

What is the value of sin^2(pi/6)+cos^2(pi/6) ?
The value of sin^2(pi/6)+cos^2(pi/6) is 1