What is the value of tan(arcsin(3/5)+arccos(-1)) ?

The value of tan(arcsin(3/5)+arccos(-1)) is 3/4

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tan(arcsin(3/5)+arccos(-1))

tan (arcsin (\frac{3}{5}) + arccos (- 1))

\frac{3}{4}

Solution steps

tan (arcsin (\frac{3}{5}) + arccos (- 1))

Rewrite using trig identities:

\frac{tan ( arcsin ( \frac{3}{5} ) ) + tan ( arccos ( - 1 ) )}{1 - tan ( arcsin ( \frac{3}{5} ) ) tan ( arccos ( - 1 ) )}

= \frac{tan ( arcsin ( \frac{3}{5} ) ) + tan ( arccos ( - 1 ) )}{1 - tan ( arcsin ( \frac{3}{5} ) ) tan ( arccos ( - 1 ) )}

Rewrite using trig identities:

tan (arcsin (\frac{3}{5})) = \frac{3}{4}

Rewrite using trig identities:

tan (arccos (- 1)) = 0

= \frac{\frac{3}{4} + 0}{1 - \frac{3}{4} \cdot 0}

Simplify

= \frac{3}{4}

arccos (\frac{24}{25})

sin^{8} (\frac{π}{2})

sin (3 0^{\circ}) + sin (3 0^{\circ})

6 sin (8 0^{\circ})

sin (\frac{π}{15})

What is the value of tan(arcsin(3/5)+arccos(-1)) ?
The value of tan(arcsin(3/5)+arccos(-1)) is 3/4