What is the value of ((tan(0)+1)-(tan(-pi/6)+1))/(0+pi/6) ?

The value of ((tan(0)+1)-(tan(-pi/6)+1))/(0+pi/6) is (2sqrt(3))/pi

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((tan(0)+1)-(tan(-pi/6)+1))/(0+pi/6)

\frac{( tan ( 0 ) + 1 ) - ( tan ( - \frac{π}{6} ) + 1 )}{0 + \frac{π}{6}}

\frac{2 3}{π}

Solution steps

\frac{( tan ( 0 ) + 1 ) - ( tan ( - \frac{π}{6} ) + 1 )}{0 + \frac{π}{6}}

= \frac{tan ( 0 ) + 1 - ( tan ( - \frac{π}{6} ) + 1 )}{0 + \frac{π}{6}}

Use the following trivial identity:

tan (0) = 0

Rewrite using trig identities:

tan (- \frac{π}{6}) = - \frac{3}{3}

= \frac{0 + 1 - ( - \frac{3}{3} + 1 )}{0 + \frac{π}{6}}

Simplify

\frac{0 + 1 - ( - \frac{3}{3} + 1 )}{0 + \frac{π}{6}} : \frac{2 3}{π}

= \frac{2 3}{π}

sin^{2} (15 0^{\circ})

arctan (tan (\frac{11 π}{9}))

- 2 sin (\frac{3 π}{2})

sin (5)

- 4 cos (\frac{π}{3}) (1 + ln (7 sin (\frac{π}{3})))

What is the value of ((tan(0)+1)-(tan(-pi/6)+1))/(0+pi/6) ?
The value of ((tan(0)+1)-(tan(-pi/6)+1))/(0+pi/6) is (2sqrt(3))/pi