What is the value of sin(960) ?

The value of sin(960) is -(sqrt(3))/2

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sin(960)

sin (96 0^{\circ})

- \frac{3}{2}

Solution steps

sin (96 0^{\circ})

sin (96 0^{\circ}) = sin (24 0^{\circ})

= sin (24 0^{\circ})

Rewrite using trig identities:

sin (18 0^{\circ}) cos (6 0^{\circ}) + cos (18 0^{\circ}) sin (6 0^{\circ})

= sin (18 0^{\circ}) cos (6 0^{\circ}) + cos (18 0^{\circ}) sin (6 0^{\circ})

Use the following trivial identity:

sin (18 0^{\circ}) = 0

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

Use the following trivial identity:

cos (18 0^{\circ}) = (- 1)

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

= 0 \cdot \frac{1}{2} + (- 1) \frac{3}{2}

Simplify

= - \frac{3}{2}

arctan (\frac{5 3}{- 5})

arcsin (\frac{73}{83})

sin (2 π)

0 sin (\frac{1}{0})

sin (6 0^{\circ}) cos (4 5^{\circ})