What is the general solution for sin(2x)=-(sqrt(3))/2 ?

The general solution for sin(2x)=-(sqrt(3))/2 is x=(2pi)/3+pin,x=(5pi)/6+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(2x)=-(sqrt(3))/2

sin (2 x) = - \frac{3}{2}

x = \frac{2 π}{3} + πn, x = \frac{5 π}{6} + πn

Solution steps

sin (2 x) = - \frac{3}{2}

General solutions for

sin (2 x) = - \frac{3}{2}

2 x = \frac{4 π}{3} + 2 πn, 2 x = \frac{5 π}{3} + 2 πn

Solve

2 x = \frac{4 π}{3} + 2 πn : x = \frac{2 π}{3} + πn

Solve

2 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{6} + πn

x = \frac{2 π}{3} + πn, x = \frac{5 π}{6} + πn

sin (2 x) = \frac{1}{2}

arctan (4)

cos (\frac{π}{3})

sinh (1)

tan (- \frac{π}{3})

What is the general solution for sin(2x)=-(sqrt(3))/2 ?
The general solution for sin(2x)=-(sqrt(3))/2 is x=(2pi)/3+pin,x=(5pi)/6+pin