What is the value of 6(cos(240)+isin(240)) ?

The value of 6(cos(240)+isin(240)) is -3-3sqrt(3)i

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6(cos(240)+isin(240))

6 (cos (24 0^{\circ}) + i sin (24 0^{\circ}))

- 3 - 33 i

Solution steps

6 (cos (24 0^{\circ}) + i sin (24 0^{\circ}))

Rewrite using trig identities:

cos (24 0^{\circ}) = - \frac{1}{2}

Rewrite using trig identities:

sin (24 0^{\circ}) = - \frac{3}{2}

= 6 (- \frac{1}{2} + i (- \frac{3}{2}))

Simplify

6 (- \frac{1}{2} + i (- \frac{3}{2})) : - 3 - 33 i

= - 3 - 33 i

18 sin (3 0^{\circ})

3 cos (- \frac{π}{4})

cos (arccos (0.87))

300 \cdot cos (3 0^{\circ})

e^{- 1} (4 sin (1) - 2.5 cos (1))

What is the value of 6(cos(240)+isin(240)) ?
The value of 6(cos(240)+isin(240)) is -3-3sqrt(3)i