What is the value of sin(pi/4)+tan(pi/6) ?

The value of sin(pi/4)+tan(pi/6) is (3sqrt(2)+2sqrt(3))/6

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Popular >

sin(pi/4)+tan(pi/6)

Solution

sin (\frac{π}{4}) + tan (\frac{π}{6})

Solution

\frac{3 2 + 2 3}{6}

Decimal Notation

1.28445 \dots

Solution steps

sin (\frac{π}{4}) + tan (\frac{π}{6})

Use the following trivial identity:

sin (\frac{π}{4}) = \frac{2}{2}

sin (\frac{π}{4})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

Use the following trivial identity:

tan (\frac{π}{6}) = \frac{3}{3}

tan (\frac{π}{6})

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= \frac{3}{3}

= \frac{2}{2} + \frac{3}{3}

Simplify

\frac{2}{2} + \frac{3}{3} : \frac{3 2 + 2 3}{6}

\frac{2}{2} + \frac{3}{3}

Least Common Multiplier of

2, 3 : 6

2, 3

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

2

3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{2}{2} :

multiply the denominator and numerator by

3

\frac{2}{2} = \frac{2 \cdot 3}{2 \cdot 3} = \frac{2 \cdot 3}{6}

For

\frac{3}{3} :

multiply the denominator and numerator by

2

\frac{3}{3} = \frac{3 \cdot 2}{3 \cdot 2} = \frac{3 \cdot 2}{6}

= \frac{2 \cdot 3}{6} + \frac{3 \cdot 2}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 + 3 \cdot 2}{6}

Factor

23 + 32 : 3 (6 + 2)

2 \cdot 3 + 3 \cdot 2

3 = 33

= 233 + 3 \cdot 2

Factor out common term

3

= 3 (23 + 2)

Refine

= 3 (2 + 6)

= \frac{3 ( 6 + 2 )}{6}

Factor

6 : 2 \cdot 3

Factor

6 = 2 \cdot 3

= \frac{3 ( 2 + 6 )}{2 \cdot 3}

Cancel

\frac{3 ( 6 + 2 )}{2 \cdot 3} : \frac{6 + 2}{2 3}

\frac{3 ( 6 + 2 )}{2 \cdot 3}

Apply radical rule:

3 = 3^{\frac{1}{2}}

= \frac{3 ^{\frac{1}{2}} ( 2 + 6 )}{2 \cdot 3}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{3 ^{\frac{1}{2}}}{3 ^{1}} = \frac{1}{3 ^{1 - \frac{1}{2}}}

= \frac{6 + 2}{2 \cdot 3 ^{- \frac{1}{2} + 1}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{6 + 2}{2 \cdot 3 ^{\frac{1}{2}}}

Apply radical rule:

3^{\frac{1}{2}} = 3

= \frac{6 + 2}{2 3}

= \frac{6 + 2}{2 3}

Rationalize

\frac{6 + 2}{2 3} : \frac{3 2 + 2 3}{6}

\frac{6 + 2}{2 3}

Multiply by the conjugate

\frac{3}{3}

= \frac{( 6 + 2 ) 3}{2 3 3}

(6 + 2) 3 = 32 + 23

(6 + 2) 3

= 3 (6 + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = 3, b = 6, c = 2

= 36 + 3 \cdot 2

= 36 + 23

36 = 32

36

Factor integer

6 = 3 \cdot 2

= 3 3 \cdot 2

Apply radical rule:

3 \cdot 2 = 32

= 332

Apply radical rule:

a a = a

33 = 3

= 32

= 32 + 23

233 = 6

233

Apply radical rule:

a a = a

33 = 3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= \frac{3 2 + 2 3}{6}

= \frac{3 2 + 2 3}{6}

= \frac{3 2 + 2 3}{6}

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Frequently Asked Questions (FAQ)

What is the value of sin(pi/4)+tan(pi/6) ?
The value of sin(pi/4)+tan(pi/6) is (3sqrt(2)+2sqrt(3))/6