What is the value of tan(arcsin(5/13)-arccos(1)) ?

The value of tan(arcsin(5/13)-arccos(1)) is 5/12

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tan(arcsin(5/13)-arccos(1))

tan (arcsin (\frac{5}{13}) - arccos (1))

\frac{5}{12}

Solution steps

tan (arcsin (\frac{5}{13}) - arccos (1))

Rewrite using trig identities:

\frac{tan ( arcsin ( \frac{5}{13} ) ) - tan ( arccos ( 1 ) )}{1 + tan ( arcsin ( \frac{5}{13} ) ) tan ( arccos ( 1 ) )}

= \frac{tan ( arcsin ( \frac{5}{13} ) ) - tan ( arccos ( 1 ) )}{1 + tan ( arcsin ( \frac{5}{13} ) ) tan ( arccos ( 1 ) )}

Rewrite using trig identities:

tan (arcsin (\frac{5}{13})) = \frac{5}{12}

Rewrite using trig identities:

tan (arccos (1)) = 0

= \frac{\frac{5}{12} - 0}{1 + \frac{5}{12} \cdot 0}

Simplify

= \frac{5}{12}

\frac{0.6}{sin ( 3 7 ^{\circ} )}

- 4 cos (2 π)

2 sin (13 5^{\circ})

arcsin (\frac{15}{16})

sin (- \frac{23 π}{6})

What is the value of tan(arcsin(5/13)-arccos(1)) ?
The value of tan(arcsin(5/13)-arccos(1)) is 5/12