What is the value of -4sin((3pi)/2)-3cos((3pi)/2) ?

The value of -4sin((3pi)/2)-3cos((3pi)/2) is 4

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-4sin((3pi)/2)-3cos((3pi)/2)

- 4 sin (\frac{3 π}{2}) - 3 cos (\frac{3 π}{2})

4

Solution steps

- 4 sin (\frac{3 π}{2}) - 3 cos (\frac{3 π}{2})

Rewrite using trig identities:

sin (\frac{3 π}{2}) = - 1

Rewrite using trig identities:

cos (\frac{3 π}{2}) = 0

= - 4 (- 1) - 3 \cdot 0

Simplify

= 4

\frac{cos ( 4 )}{4}

sin (3 (\frac{π}{4}))

cos (8 0^{\circ}) cos (1 0^{\circ}) - sin (8 0^{\circ}) sin (1 0^{\circ})

cot (5 4^{\circ})

arccot (- 8)

What is the value of -4sin((3pi)/2)-3cos((3pi)/2) ?
The value of -4sin((3pi)/2)-3cos((3pi)/2) is 4