What is the value of tan(arcsin(12/13)+arccos(-1)) ?

The value of tan(arcsin(12/13)+arccos(-1)) is 12/5

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tan(arcsin(12/13)+arccos(-1))

tan (arcsin (\frac{12}{13}) + arccos (- 1))

\frac{12}{5}

Solution steps

tan (arcsin (\frac{12}{13}) + arccos (- 1))

Rewrite using trig identities:

\frac{tan ( arcsin ( \frac{12}{13} ) ) + tan ( arccos ( - 1 ) )}{1 - tan ( arcsin ( \frac{12}{13} ) ) tan ( arccos ( - 1 ) )}

= \frac{tan ( arcsin ( \frac{12}{13} ) ) + tan ( arccos ( - 1 ) )}{1 - tan ( arcsin ( \frac{12}{13} ) ) tan ( arccos ( - 1 ) )}

Rewrite using trig identities:

tan (arcsin (\frac{12}{13})) = \frac{12}{5}

Rewrite using trig identities:

tan (arccos (- 1)) = 0

= \frac{\frac{12}{5} + 0}{1 - \frac{12}{5} \cdot 0}

Simplify

= \frac{12}{5}

sin (π^{4})

arctan (\frac{11}{9})

arctan (- \frac{4}{0})

cos^{2} (2 0^{\circ}) - sin^{2} (2 0^{\circ})

arcsin (\frac{3 π}{4})

What is the value of tan(arcsin(12/13)+arccos(-1)) ?
The value of tan(arcsin(12/13)+arccos(-1)) is 12/5