What is the value of sin(72)cos(42)-cos(72)sin(42) ?

The value of sin(72)cos(42)-cos(72)sin(42) is 1/2

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sin(72)cos(42)-cos(72)sin(42)

sin (7 2^{\circ}) cos (4 2^{\circ}) - cos (7 2^{\circ}) sin (4 2^{\circ})

\frac{1}{2}

Solution steps

sin (7 2^{\circ}) cos (4 2^{\circ}) - cos (7 2^{\circ}) sin (4 2^{\circ})

Rewrite using trig identities:

sin (3 0^{\circ})

= sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

= \frac{1}{2}

35 sin (4 0^{\circ})

tan (- \frac{23 π}{6})

sin (2) (2 π)

\frac{1}{tan ( 3 6 ^{\circ} )}

arccsc (- \frac{6}{5})

What is the value of sin(72)cos(42)-cos(72)sin(42) ?
The value of sin(72)cos(42)-cos(72)sin(42) is 1/2