What is the value of sin(2pi)-cos(2pi) ?

The value of sin(2pi)-cos(2pi) is -1

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sin(2pi)-cos(2pi)

sin (2 π) - cos (2 π)

- 1

Solution steps

sin (2 π) - cos (2 π)

sin (2 π) = sin (0)

= sin (0) - cos (2 π)

cos (2 π) = cos (0)

= sin (0) - cos (0)

Use the following trivial identity:

sin (0) = 0

Use the following trivial identity:

cos (0) = 1

= 0 - 1

Simplify

= - 1

tan (\frac{7 π}{5})

5 sin (9 0^{\circ})

cos^{3} (- \frac{3}{2}) + (- \frac{3}{2})^{4} - 3

cos (cos (0))

\frac{8}{sin ( 6 2 ^{\circ} )}