What is the value of sin(42)cos(48)+cos(42)sin(48) ?

The value of sin(42)cos(48)+cos(42)sin(48) is 1

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sin(42)cos(48)+cos(42)sin(48)

sin (4 2^{\circ}) cos (4 8^{\circ}) + cos (4 2^{\circ}) sin (4 8^{\circ})

1

Solution steps

sin (4 2^{\circ}) cos (4 8^{\circ}) + cos (4 2^{\circ}) sin (4 8^{\circ})

Rewrite using trig identities:

sin (9 0^{\circ})

= sin (9 0^{\circ})

Use the following trivial identity:

sin (9 0^{\circ}) = 1

= 1

cos (arcsin (\frac{5}{13}) + arctan (\frac{4}{3}))

cot (\frac{5}{12})

1 + sin (\frac{7 π}{4})

sin (- \frac{π}{6} - 2 ln (3 i))

6 + 3 cos (\frac{π}{2})

What is the value of sin(42)cos(48)+cos(42)sin(48) ?
The value of sin(42)cos(48)+cos(42)sin(48) is 1