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two fair dice are rolled. what is the probability of rolling a sum not more than 6

Solution

two fair dice are rolled. what is the probability of rolling a sum not more than 6

Solution

\frac{5}{12}

Solution steps

The possible outcomes when two dice are rolled are

6 \cdot 6

Therefore, the number of possible outcomes:

6^{2}

Find the number of favorable outcomes of rolling a sum no more than 6:

15

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{15}{6 ^{2}}

\frac{15}{6 ^{2}} = \frac{5}{12}

= \frac{5}{12}

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