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A fair dice is thrown twice.Find the probability that at least one of the numbers obtained is a prime number.

Solution

A fair dice is thrown twice.Find the probability that at least one of the numbers obtained is a prime number.

Solution

\frac{11}{36}

Solution steps

Find the probability of no 1:

\frac{25}{36}

Probability of at least 1 of the numbers obtained is a prime number

= 1 -

Probability of no 1

= 1 - \frac{25}{36}

1 - \frac{25}{36} = \frac{11}{36}

= \frac{11}{36}

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