Two years ago, a father was four times older than his son. In twelve years’ time, he will be twice as old as his son. Find the ages of both the father and his son.

Solution

Solution

Father^{'} s age is : 30

Boy^{'} s age is : 9

Solution steps

Translate the problem into an equation:

x - 2 = 4 (y - 2), x + 12 = 2 (y + 12)

x - 2 = 4 (y - 2), x + 12 = 2 (y + 12) : x = 30, y = 9

Father^{'} s age is : 30

Boy^{'} s age is : 9

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