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Popular >

The sum of the squares of two consecutive integers is 41 . Find the integers.

Solution

The sum of the squares of two consecutive integers is 41 . Find the integers.

Solution

The numbers : 4, 5 or - 5, - 4

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} + (x + 1)^{2} = 41

Solve

x^{2} + (x + 1)^{2} = 41 : x = 4, x = - 5

Plug in

x = 4 : 5

Plug in

x = - 5 : - 4

The numbers : 4, 5 or - 5, - 4

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