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What is the probability that the three cards dealt are, in order, an ace, a face card, and a 2? (A face card is a jack, queen, or king.)

Solution

What is the probability that the three cards dealt are, in order, an ace, a face card, and a 2? (A face card is a jack, queen, or king.)

Solution

\frac{1}{13}

Solution steps

Find the probability of getting ace face and getting 2 face jack queen :

0

Find the probability of getting 2 face jack queen :

0

Find the probability of king.:

\frac{1}{13}

Since the events are disjoint, Use the formula

P (X_{1} \lor X_{2} \lor \dots \lor X_{k}) = P (X_{1}) + P (X_{2}) + \dots + P (X_{k})

= 0 + 0 + \frac{1}{13}

Apply rule:

a + 0 = a

= \frac{1}{13}

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