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Popular >

The sum of the squares of two consecutive positive odd integers is 202. find the integers.

Solution

The sum of the squares of two consecutive positive odd integers is 202. find the integers.

Solution

The numbers : 9, 11

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 2

A.T.Q.:

x^{2} + (x + 2)^{2} = 202

Solve

x^{2} + (x + 2)^{2} = 202 : x = 9, x = - 11

Select positive solutions:

9

x + 2 = 9 + 2 = 11

The numbers : 9, 11

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