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Two fair dice are thrown twice. What is the probability that at least one of the numbers obtained is prime number

Solution

Two fair dice are thrown twice. What is the probability that at least one of the numbers obtained is prime number

Solution

\frac{11}{36}

Solution steps

Find the probability of no 1:

\frac{25}{36}

Probability of at least 1 of the numbers obtained is prime number

= 1 -

Probability of no 1

= 1 - \frac{25}{36}

1 - \frac{25}{36} = \frac{11}{36}

= \frac{11}{36}

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