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Popular >

Find 3 consecutive integers such that 4 times the sum of the 1st and the 3rd is 14 greater than 7 times the second.

Solution

Find 3 consecutive integers such that 4 times the sum of the 1st and the 3rd is 14 greater than 7 times the second.

Solution

The numbers : 13, 14, 15

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 1

Consecutive number 2 : x + 2

A.T.Q.:

4 (x + x + 2) = 14 + 7 (x + 1)

Solve

4 (x + x + 2) = 14 + 7 (x + 1) : x = 13

x + 1 = 13 + 1 = 14

x + 2 = 13 + 2 = 15

The numbers : 13, 14, 15

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