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the sum of the squares of two consecutive integers is 9 greater than 8 times the smaller integer. find the integers

الحلّ

the sum of the squares of two consecutive integers is 9 greater than 8 times the smaller integer. find the integers

الحلّ

The numbers : 4, 5 or - 1, 0

خطوات الحلّ

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} + (x + 1)^{2} = 9 + 8 x

x^{2} + (x + 1)^{2} = 9 + 8 x

حلّ:

x = 4, x = - 1

x = 4

استبدل:

5

x = - 1

استبدل:

0

The numbers : 4, 5 or - 1, 0

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