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Popular >

the sum of the squares of two consecutive integers is 9 greater than 8 times the smaller integer. find the integers

Solution

the sum of the squares of two consecutive integers is 9 greater than 8 times the smaller integer. find the integers

Solution

The numbers : 4, 5 or - 1, 0

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

x^{2} + (x + 1)^{2} = 9 + 8 x

Solve

x^{2} + (x + 1)^{2} = 9 + 8 x : x = 4, x = - 1

Plug in

x = 4 : 5

Plug in

x = - 1 : 0

The numbers : 4, 5 or - 1, 0

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