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Popular >

Find two consecutive integers such that the square of the larger integer is ninteen more than nine times the smaller integer

Solution

Find two consecutive integers such that the square of the larger integer is ninteen more than nine times the smaller integer

Solution

The numbers : 9, 10 or - 2, - 1

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

(x + 1)^{2} = 19 + 9 x

Solve

(x + 1)^{2} = 19 + 9 x : x = 9, x = - 2

Plug in

x = 9 : 10

Plug in

x = - 2 : - 1

The numbers : 9, 10 or - 2, - 1

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