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the sum of three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer

Решение

the sum of three consecutive odd integers such that seven times the sum of the first two integers is three more than nine times the third integer

Решение

The numbers : - 5 \frac{2}{7}, - 3 \frac{2}{7}, - 1 \frac{2}{7}

Шаги решения

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x + x + 2 = 3 + 9 (x + 4)

Решить

x + x + 2 = 3 + 9 (x + 4) : x = - \frac{37}{7}

x + 2 = - \frac{37}{7} + 2 = - \frac{23}{7}

x + 4 = - \frac{37}{7} + 4 = - \frac{9}{7}

Преобразуйте неправильные дроби в смешанные числа:

\frac{37}{7} = 5 \frac{2}{7}

Преобразуйте неправильные дроби в смешанные числа:

\frac{23}{7} = 3 \frac{2}{7}

Преобразуйте неправильные дроби в смешанные числа:

\frac{9}{7} = 1 \frac{2}{7}

The numbers : - 5 \frac{2}{7}, - 3 \frac{2}{7}, - 1 \frac{2}{7}

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