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Find the probability that in five tosses of a fair die a 3 appears once,

Solution

Find the probability that in five tosses of a fair die a 3 appears once,

Solution

\frac{1}{6}

Solution steps

The possible outcomes when \mathrm{a die is rolled} is

{1, 2, 3, 4, 5, 6} .

Therefore, the number of possible outcomes:

6

The number of favorable outcomes of \mathrm{in 5 tosses of a fair die a 3 appears once}:

1

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{1}{6}

Popular Examples

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