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An ordinary die is tossed. What is the probability of getting a 3 or a 4?

Solution

An ordinary die is tossed. What is the probability of getting a 3 or a 4?

Solution

\frac{1}{3}

Solution steps

Find the probability of getting a 3:

\frac{1}{6}

Find the probability of a 4:

\frac{1}{6}

Since the events are disjoint, Use the formula

P (X_{1} \lor X_{2} \lor \dots \lor X_{k}) = P (X_{1}) + P (X_{2}) + \dots + P (X_{k})

= \frac{1}{6} + \frac{1}{6}

\frac{1}{6} + \frac{1}{6} = \frac{1}{3}

= \frac{1}{3}

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