The sum of three integers is 37. The sum of the first and second integers exceeds the third by 45. The third integer is 20 less than the first. Find the three integers.

Soluzione

Soluzione

The numbers : 11 \frac{2}{3}, 33 \frac{2}{3}, - 8 \frac{1}{3}

Fasi della soluzione

Represent the numbers with

x, y, z

number 1 : x

number 2 : y

number 3 : z

A.T.Q.:

x + y + z = 37

x + y = \frac{1}{3} + 45

z = x - 20

x + y + z = 37, x + y = \frac{1}{3} + 45, z = x - 20 : x = \frac{35}{3}, y = \frac{101}{3}, z = - \frac{25}{3}

Convertire frazioni improprie in numeri misti:

\frac{35}{3} = 11 \frac{2}{3}

Convertire frazioni improprie in numeri misti:

\frac{101}{3} = 33 \frac{2}{3}

Convertire frazioni improprie in numeri misti:

\frac{25}{3} = 8 \frac{1}{3}

The numbers : 11 \frac{2}{3}, 33 \frac{2}{3}, - 8 \frac{1}{3}

Esempi popolari

the square root of four more than twice a number The circonferenza of a circle is 20pi in. What is the area, in square inches? Express your answer in terms of 4 less than a number.What is the radius of a circle with a diametro of 4 The sum of three consecutive even integers is-108