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two dice are rolled. What is the probability that the sum of the numbers rolled is a number greater than 9?

Solution

two dice are rolled. What is the probability that the sum of the numbers rolled is a number greater than 9?

Solution

\frac{1}{6}

Solution steps

The possible outcomes when two dice are rolled are

6 \cdot 6

Therefore, the number of possible outcomes:

6^{2}

Find the number of favorable outcomes of the sum of the numbers rolled is a number greater than 9:

6

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{6}{6 ^{2}}

Cancel the common factor:

6

= \frac{1}{6}

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