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two cyclists leave towns 185 miles apart at the same time and travel toward each other. One cyclist travels 9 miles per hour faster than the other. If they meet in 5 hours, what is the rate of each cyclists?

Solution

Solution

first cyclis t^{'} s speed : 23

second cyclis t^{'} s speed : 14

Solution steps

Translate the problem into an equation:

x \cdot 5 + (x - 9) \cdot 5 = 185

Solve for

x, x \cdot 5 + (x - 9) \cdot 5 = 185 : x = 23

Find speed

first cyclis t^{'} s speed : 23

second cyclis t^{'} s speed : 14

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