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Find four consecutive odd integers such that 6 times the sum of the first and the third is3 more than 5 times the opposite of the fourth.

Solution

Find four consecutive odd integers such that 6 times the sum of the first and the third is3 more than 5 times the opposite of the fourth.

Solution

No Solution

Solution steps

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

Consecutive number 3 : x + 6

A.T.Q.:

6 (x + \frac{1}{3}) = 3 + 5 (- (x + 6))

Solve

6 (x + \frac{1}{3}) = 3 + 5 (- (x + 6)) : x = - \frac{29}{11}

x + 2 = - \frac{29}{11} + 2 = - \frac{7}{11}

x + 4 = - \frac{29}{11} + 4 = \frac{15}{11}

x + 6 = - \frac{29}{11} + 6 = \frac{37}{11}

Even value

- \frac{29}{11}

discarded

No Solution

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