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in a game, a player tosses a coin four times, what is the probability of getting two heads?

Solution

in a game, a player tosses a coin four times, what is the probability of getting two heads?

Solution

\frac{3}{8}

Solution steps

The possible outcomes when a coin is thrown four times are

2 \cdot 2 \cdot 2 \cdot 2

Therefore, the number of possible outcomes:

2^{4}

Find the number of favorable outcomes of getting 2 heads:

6

Probability

= \frac{number of favorable outcomes}{total number of outcomes}

= \frac{6}{2 ^{4}}

\frac{6}{2 ^{4}} = \frac{3}{8}

= \frac{3}{8}

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