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Popular >

Find two positive even consecutive integers such that the square of the smaller integer is 10 more than the larger integer.

Solution

Find two positive even consecutive integers such that the square of the smaller integer is 10 more than the larger integer.

Solution

The number : 2 \frac{1}{2} or - 2

Solution steps

Represent the number with

x

A.T.Q.:

2 x^{2} = 10 + x

Solve for

x, 2 x^{2} = 10 + x : x = \frac{5}{2}, x = - 2

Convert improper fractions to mixed numbers:

\frac{5}{2} = 2 \frac{1}{2}

The number : 2 \frac{1}{2} or - 2

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