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Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 65 km/h faster than the other. If the two planes are 14175 kilometers apart after 9 hours, what is the rate of each plane?

Solution

Solution

first plan e^{'} s speed : 820

second plan e^{'} s speed : 755

Solution steps

Translate the problem into an equation:

x \cdot 9 + (x - 65) \cdot 9 = 14175

Solve for

x, x \cdot 9 + (x - 65) \cdot 9 = 14175 : x = 820

Find speed

first plan e^{'} s speed : 820

second plan e^{'} s speed : 755

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