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range of (4x^2-36x)/(x-9)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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range 4x²−36xx−9

Solution

f(x)<36 or f(x)>36

Interval Notation

(−∞ , 36)∪(36, ∞ )

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Function range definition

The set of values of the dependent variable for which a function is defined

Find the minimum and maximum value in each defined interval and unite the results

Domain of 4x²−36xx−9 : x<9 or x>9

Simplify 4x²−36xx−9 : 4x

Extreme Points of 4x: None

Find the range for the interval −∞ <x<9: −∞ <f(x)<36

Find the range for the interval 9<x<∞ : 36<f(x)<∞

Combine the ranges of all domain intervals to obtain the function range

f(x)<36 or f(x)>36

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domain 4x²−36xx−9

inverse 4x²−36xx−9

intercepts 4x²−36xx−9

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

range of (4x^2-36x)/(x-9)

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