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linear y^{\prime \prime}-6y^{\prime}+15y=2sin(3t),y(0)=-1,y^{\prime}(0)=-4

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linear y^{′ ′}−6y^′+15y=2sin(3t), y(0)=−1, y^′(0)=−4

Solution

y=e^3t(−1110 cos(√6t)−2√25√3 sin(√6t))+130 sin(3t)+110 cos(3t)

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y′ ′ −6y′ +15y=2sin(3t)

Solve linear ODE: y=e^3t(−1110 cos(√6t)−2√25√3 sin(√6t))+130 sin(3t)+110 cos(3t)

y=e^3t(−1110 cos(√6t)−2√25√3 sin(√6t))+130 sin(3t)+110 cos(3t)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

linear y^{\prime \prime}-6y^{\prime}+15y=2sin(3t),y(0)=-1,y^{\prime}(0)=-4

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