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2y'-y=4sin(3t)

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2y^′−y=4sin(3t)

Solution

y=−4(6cos(3t)+sin(3t))37 +c₁e^12 t

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2y′ −y=4sin(3t)

Solve linear ODE: y=−4(6cos(3t)+sin(3t))37 +c₁e^12 t

y=−4(6cos(3t)+sin(3t))37 +c₁e^12 t

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

2y'-y=4sin(3t)

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