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vertices (x-4)^2+(y+2)^2=25

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for partial fractions long division line

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long division (a⁶+2a⁵−3a³−2a⁴−a−1)(a⁵+a²−a+1)

Solution

a+2+−2a⁴−4a³−a²−3a⁵+a²−a+1

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Solution steps

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(a⁶+2a⁵−3a³−2a⁴−a−1)(a⁵+a²−a+1)

Divide a⁶+2a⁵−2a⁴−3a³−a−1a⁵+a²−a+1

=a+2a⁵−2a⁴−4a³+a²−2a−1a⁵+a²−a+1

Divide 2a⁵−2a⁴−4a³+a²−2a−1a⁵+a²−a+1

=a+2+−2a⁴−4a³−a²−3a⁵+a²−a+1

Solve instead

f(a)=(a⁶+2a⁵−3a³−2a⁴−a−1)(a⁵+a²−a+1)

dda ((a⁶+2a⁵−3a³−2a⁴−a−1)(a⁵+a²−a+1) )

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

vertices (x-4)^2+(y+2)^2=25

Solution

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