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inverse of (4x^2-36x)/(x-9)

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parity x³−2x²−3xx²−4

Solution

Neither even nor odd

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25x²+4y²+100x−40y=400

Ellipse standard equation

(x−h)²a² +(y−k)²b² =1 is the ellipse standard equation
with center (h, k) and a, b are the semi-major and semi-minor axes

Rewrite 25x²+4y²+100x−40y=400 in the form of the standard ellipse equation

(x−(−2))²(2√6)² +(y−5)²(5√6)² =1

Therefore ellipse properties are:

(h, k)=(−2, 5), a=2√6, b=5√6

b>a therefore b is semi-major axis and a is semi-minor axis

Ellipse with center (h, k)=(−2, 5), b=5√6, a=2√6

And the center is:

(−2, 5)

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domain x³−2x²−3xx²−4

range x³−2x²−3xx²−4

intercepts x³−2x²−3xx²−4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of (4x^2-36x)/(x-9)

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