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x2 x□ log□ √☐ □√☐ ≤ ≥ □□  · ÷ x◦ π
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▭ |▭ ×▭▭ +▭▭ −▭▭ ( ) × ☐☐☐ 
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Solutions > EN: pre-calculus-function-shift-calculator title >

derivative of ((2x^3+11x^2+5x)/((2x^2+x)))

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x2 x□ log□ √☐ □√☐ ≤ ≥ □□  · ÷ x◦ π
(☐)′ ddx  ∂∂x  ∫ ∫□□ lim ∑ ∞ θ (f ◦ g) f(x)
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▭ |▭ ) . 0 = + y
Basic αβγ ABΓ sincos ≥÷→ x ℂ∀ ∑ ∫ ∏ (
☐☐
☐☐
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☐2 x☐ √☐ □√☐ □□  log□ π θ ∞ ∫ ddx 
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lim limx→∞ limx→0+ limx→0− ddx  d2dx2  (☐)′ (☐)′′ ∂∂x 
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ddx ((2x3+11x2+5x)(2x2+x) )
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ddx ((2x3+11x2+5x)(2x2+x) )
 
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Solution

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Related
  • $$\int\frac{\left(2x^{3}+11x^{2}+5x\right)}{\left(2x^{2}+x\right)}dx$$
  • $$\lim_{x\to\infty#}\left(\frac{\left(2x^{3}+11x^{2}+5x\right)}{\left(2x^{2}+x\right)}\right)$$
  • inverse laplace $$\frac{\left(2x^{3}+11x^{2}+5x\right)}{\left(2x^{2}+x\right)}$$
Function Shift Examples
  • shift y=2sin(2x)+3
  • shift f(x)=sin(x)
  • shift f(x)=2cos(2x−1)+4
  • shift f(x)=cos(x)−3
  • shift y=tan(2x−5)
Description
Find phase and vertical shift of periodic functions step-by-step

pre-calculus-function-shift-calculator

$$\frac{d}{dx}\left(\frac{\left(2x^{3}+11x^{2}+5x\right)}{\left(2x^{2}+x\right)}\right)$$

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