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inverse of -((x+3)^2)/(20)+1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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periodicity 3cos(2x+π4 )+1

Solution

Decimal

3.14159…

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Periodicity of a·cos(bx + c) + d=periodicity of cos(x)|b|

Periodicity of cos(x) is 2π

=2π|2|

Simplify

=π

Solve instead

domain 3cos(2x+π4 )+1

range 3cos(2x+π4 )+1

amplitude 3cos(2x+π4 )+1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse of -((x+3)^2)/(20)+1

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