5y-4 =-3x in standard form

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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standard form 5y−4=−3x

Solution

3x+5y=4

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Solution steps

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5y−4=−3x

Standard form definition

Ax+By=C is the standard form of a line, A is positive integer, B, C are integers

Add 4 to both sides

5y−4+4=−3x+4

Simplify

5y=−3x+4

Add 3x to both sides

5y+3x=−3x+4+3x

Simplify

3x+5y=4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

5y-4 =-3x in standard form

Solution

Solution steps

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