d/(dq)(sin(2q)+cos^2(q))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplify solve for inverse tangent line

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ddq (sin(2q)+cos²(q))

Solution

cos(2q)· 2−sin(2q)

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ddq (sin(2q)+cos²(q))

Apply the Sum/Difference Rule: (f±g)′=f ′±g′

=ddq (sin(2q))+ddq (cos²(q))

ddq (sin(2q))=cos(2q)· 2

ddq (cos²(q))=−sin(2q)

=cos(2q)· 2−sin(2q)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

d/(dq)(sin(2q)+cos^2(q))

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