derivative of (x^4/(3-x^3))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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ddx (x⁴3−x³ )

Solution

12x³−x⁶(3−x³)²

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ddx (x⁴3−x³ )

Apply the Quotient Rule: (fg )^′=f ′·g−g′·fg²

=ddx (x⁴)(3−x³)−ddx (3−x³)x⁴(3−x³)²

ddx (x⁴)=4x³

ddx (3−x³)=−3x²

=4x³(3−x³)−(−3x²)x⁴(3−x³)²

Simplify 4x³(3−x³)−(−3x²)x⁴(3−x³)² : 12x³−x⁶(3−x³)²

=12x³−x⁶(3−x³)²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (x^4/(3-x^3))

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